How come a bouncing ball does not exhibit SHM characteristics?

AI Thread Summary
A bouncing ball does not exhibit simple harmonic motion (SHM) characteristics primarily because it lacks a restoring force that would return it to its original position. The presence of contact forces during the bounce alters the motion, preventing the ball from maintaining a consistent oscillation pattern. While the ball may experience elastic collisions, these do not create the necessary conditions for SHM, as the time intervals between bounces decrease over time. The graph of a bouncing ball would show a curved ascent followed by a sharp drop, indicating the impact force at the ground. Ultimately, the fundamental definition of SHM requires a proportional and opposite force to displacement, which is absent in the case of a bouncing ball.
.NoStyle
Messages
35
Reaction score
0

Homework Statement


How come a bouncing ball does not exhibit SHM characteristics?


Homework Equations


no clue



The Attempt at a Solution



When I think of SHM, I don't think of contact forces. In the bouncing call case, there is a contact force present when the ball hits the ground.

Would the graph for a bouncing ball look curved as it approached it's height, but then a sharp V as it hits the ground?

Thanks
 
Physics news on Phys.org
What is the defining characteristic of a system in SHM? Does this apply to a bouncing ball?
 
Think of it this way...

As the ball bounces, why do the time intervals that the ball is in the air get smaller the longer the ball bounces... it is missing a certain force that is essential to SHM...
 
The fact that the ball is airborne for shorter periods of times after each consecutive bounce is not the reason why it doesn't count as SHM. One can envisage a hypothetical scenario where the collision of the ball with the floor is entirely elastic; no kinetic energy is lost to the floor as heat, sound etc. There is something more fundamental in the definition of SHM than that consideration.
 
Defennder said:
The fact that the ball is airborne for shorter periods of times after each consecutive bounce is not the reason why it doesn't count as SHM. One can envisage a hypothetical scenario where the collision of the ball with the floor is entirely elastic; no kinetic energy is lost to the floor as heat, sound etc. There is something more fundamental in the definition of SHM than that consideration.

maybe were on a different wavelength here, but i was hinting at... its not SHM because it has no restoring force... aka... why the ball doesn't return to its original position. I wasnt saying that's why it isn't SHM, i was using that as an example as to aid him in finding the answer.
 
.NoStyle said:

Homework Statement


How come a bouncing ball does not exhibit SHM characteristics?

Homework Equations


no clue

The Attempt at a Solution



When I think of SHM, I don't think of contact forces. In the bouncing call case, there is a contact force present when the ball hits the ground.

Would the graph for a bouncing ball look curved as it approached it's height, but then a sharp V as it hits the ground?

(By the way, a bouncing ball that is in motion in another direction exhibits what you describe with the sharp V at the impulse of the floor changing direction.

Thanks
From Wikipedia:
"In words, simple harmonic motion is "motion where the force acting on a body and thereby acceleration of the body is proportional to, and opposite in direction to the displacement from its equilibrium position" (i.e. F = − kx)."

Your instinct looks correct. The contact with the floor is an impulse force that perturbs the constant accelerated motion that it is otherwise subjected to in one direction of gravity only.)
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top