How Deep Can a Snorkeler Dive with a 1/20 Atmosphere Lung Pressure Difference?

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The discussion revolves around calculating the maximum depth a snorkeler can dive given a lung pressure difference limit of 1/20 of an atmosphere. The pressure inside the lungs is assumed to be 1 atm, leading to a calculation where the pressure difference must be less than 5065 Pa. The participant initially calculated a depth of 9.54 meters but found this to be incorrect, suggesting a misunderstanding of pressure dynamics underwater. A revised estimate of around 0.5 meters was mentioned, indicating the need for further clarification on pressure calculations. The thread highlights the complexities of pressure differences in diving scenarios and seeks accurate methods for determining safe snorkeling depths.
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Homework Statement


The human lungs can function satisfactorily up to a limit where the pressure difference between the outside and inside of the lungs is 1/20 of an atmosphere. If a diver uses a snorkel for breathing, how far below the water can she swim? Assume the diver is in salt water whose density is 1029 kg/m3.


Homework Equations


1 atm = 1.013e5 Pa
1/20 atm = 5065 Pa
P1 + P2 = gauge pressure
P = density*gravity*height
P = Force/Area

The Attempt at a Solution



So the pressure in the lungs minus the pressure outside the lungs must be less than 5065 Pa. If
P1-P2 = 5065 and
P2 = 1029*height
these should just be combined somehow. However, how do I know what the pressure is inside the lungs? If I use 1 atm,
1.013e5 - 1029(g)(h) = 5065
96235 = 1029(9.8)(h)
h = 9.54 m
But this is not correct. Does anyone have a suggestion?
 
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I would expect the pressure under water to be greater so I'd take the under water pressure away from the pressure in the lungs. The difference is not that great however.
 
Ok so any other ideas?
 
I came up with about 0.5 meters.
 
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