How Deep is the Well If a Pebble Takes 15 Seconds to Make a Splash?

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To determine the depth of the well, the total time of 15 seconds includes both the time for the pebble to fall and the time for the sound to travel back up. The problem can be solved using a quadratic equation, where the variables include the acceleration due to gravity (9.8 m/s²) and the speed of sound (343 m/s). The relationship between the time, distance, and speed allows for the calculation of the well's depth. Participants emphasize the importance of showing work to facilitate understanding and problem-solving. The discussion highlights the collaborative nature of the forum, encouraging members to assist each other with mathematical challenges.
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A pebble is dropped into a well. It takes 15 seconds for the sound of the splash to be heard. If the speed of sound is 343 m/s how deep is the well?

Please Help!
 
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There was another recent problem in a similar vein. Can you try searching for it ?

This problem involves solving a quadratic equation. Do you know how to do those ?
 
Since it's posted in the College section,it would be a shame if he didn't... :-p


Daniel.

PS.Post your work.
 
True. It seems strange that there's such a high degree of overlap between the standard of problems posed in the other forum and this one.
 
Hey guys I posted this hoping for some help not attitude towards my question, isn't that what this forum is for?
 
blair2707 said:
Hey guys I posted this hoping for some help not attitude towards my question, isn't that what this forum is for?

This forum is indeed to help.Did u read the "sticky" on top of the list of threads??

Post your work...

Daniel.

PS.We won't do the problems for you...
 
help

hint: 15 seconds is the time it takes for the pebble to fall + the time it takes for the sound to travel back up the well. Since t is a known in the equation, and the pebble falls the same height the splashing sound travels, the solution is obtainable through a quadratic function of x. You know t=15, a=g=9.8, v=343...
 

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