How did they compute this e equation?

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Homework Statement


this is a question I'm working on, and there's this step I'm stuck on
it looks like this:

Homework Equations


eq0041LP.gif



The Attempt at a Solution


how come the 9.8 became the 50?

thanks
 
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\int e^{ax}dx= \frac{1}{a}e^{ax}+C
 
rock.freak667 said:
\int e^{ax}dx= \frac{1}{a}e^{ax}+C

ohhHHHH ... it seems all simple now

thanks!
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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