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Initial Value Problem for (DE)

  1. Jan 17, 2017 #1
    1. The problem statement, all variables and given/known data
    dv/dt = 9.8 - (v/5) , v(0) = 0

    (a) The time it must elapse for the objet to reach 98% of its limiting velocity
    (b) How far does the object fall in the time found in part (a)?
    2. Relevant equations
    (dv/dt)/(9.8-(v/5))

    3. The attempt at a solution
    I'm a little overwhelmed by this class and I think the problem I have is I'm not catching on as to why the next answer is the way it is, so it would be nice if someone could explain to me why.
    As I read on my textbook, I'm supposed to rewrite the form of the eqn first in which I attempted to do:

    (dv/dt)/(9.8-(v/5)) = 1dt
    but why do we have to rewrite the eqn in this form? I checked the solution for this, and it said it was right. I know afterwards you then integrate both sides, but I saw that they got
    −5ln(9.8−(v/5))=t+C
    I understand where the t+C comes from but not where the -5ln(9.8-(v/5)) comes from. Can someone explain to me how to get to that?
     
  2. jcsd
  3. Jan 17, 2017 #2

    Orodruin

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    What is the integral of 1/x?
     
  4. Jan 17, 2017 #3
    ln(x)! Ah I missed that. Thanks!
     
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