How Do a Dog and Man Walking at Different Speeds Meet Along a 1km Path?

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A dog and a man start walking simultaneously from point A to point B, which is 1km apart, with the dog walking twice as fast as the man. They first meet at a distance of 2/3 km from point A. The pattern of their meetings can be analyzed mathematically, revealing that they will meet at consistent intervals as they continue to walk back and forth. The second and third meeting points can be calculated based on their speeds and the total distance covered. The discussion also explores how to represent this scenario using straight line graphs.
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The distance between point A and B is 1km. A dog and man start walking at the same time from point A toward point B. They will keep walking (if reached B then walk back toward A immediately, and if reached A then walk back toward B immediately, so on).

1.Given that the dog walks twice as fast as the man does.
(a) Where do they meet the first time? Show your reasoning.
(b) Where do they meet the second time? The third time? Show your reasoning.
(c) Any pattern observed?
(d) Where do they meet the 134th time?

I think I have (a) done, not sure though.
total distance = Vman x t + Vdog x t = 2
= Vman x t = 2Vman x t = 2
=3Vmant x t = 2
d=2/3 km

Not sure what to do next?? Thanks in advance!
 
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How do you suppose you could represnet this problem using straight line graphs?
 
genericusrnme said:
How do you suppose you could represnet this problem using straight line graphs?

Nice hint.
 
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