How Do Buoyant Forces Affect Submerged Objects?

AI Thread Summary
The discussion focuses on calculating the effects of buoyant forces on a submerged metal object. The first question involves determining the mass of water displaced by a 100-gram metal chunk with a density of 4 grams per cubic centimeter, leading to a volume calculation. The second question addresses the buoyant force, which is equal to the weight of the displaced fluid, calculated using the object's volume and the density of water. The third question concerns the reading on a spring scale when the metal is submerged, which requires understanding the weight difference in air and water. Overall, participants are seeking clarification on the calculations related to buoyancy and displacement.
dragon162
Messages
16
Reaction score
0

Homework Statement


note: It may make things easier to assume that g=10 m/s^2
Suppose that I have a 100 gram chunk of metal with a density of 4 grams per cubic centimeter.
1)What is the mass of water displaced by this chunk of metal?(give your answer in kg)
2)what is the buoyant force on the metal?
3)If I hang this 100 gram chunk of metal from a spring scale and lower the metal into the water what will the scale read?(give your answer in Newtons)


Homework Equations


d=m/v
S=W/(W-W_0)
S=W/(W_1-W_2)

The Attempt at a Solution



For number one I am guessing its just a simple d=m/v problem. So given the information V=0.1kg/.004 kg/cm^3= 25. But i am not sure what to do with this after.

For number two I know that the difference of the weight of the object in the air and the weight of the object when its fully submerged in water is the buoyant force exerted on the body by the water. So to get the W=mg=.1kg*10m/s^2 but i am not sure how to get W_1= the weight of the object in the water.

for part three I am just not sure what I am supposed to do.
 
Physics news on Phys.org
ok so i figured out for part two that the volume of the object is the same as the volume of the displaced water. so using the v olume i calculated i used m=dv=25(1)=25 to get the mass of the water. This correct?

as for part two, i found out that the buoyant force= to the weight of fluid displaced and to find the weight of fluid displaced its just volume of object* density of the fluid*gravity
so 25*1*10=250. Is this correct as well?

still trying to figure out part three so any help would be appreciated.
 
bump, some help please
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top