How Do Capacitors Behave in a DC Circuit?

AI Thread Summary
In a DC circuit with a 12V supply and capacitors of 12 and 4 microfarads, electron flow is anticlockwise when the switch is closed, establishing a negative charge at plate D. The total capacitance of the series arrangement can be calculated, but the specific value was not provided. The charge distribution on each plate after the circuit stabilizes needs clarification, particularly regarding the isolated electrons between plates B and C. Introducing a 1 megaohm resistor between plates B and C would impact the charge dynamics and potentially the overall capacitance, although specific effects were not detailed. Further analysis is required to fully understand the implications of these components on the circuit behavior.
Jamessamuel
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Homework Statement


A 12V DC supply is connected in series to 2 capacitors, of 12 and 4 micro farads. A switch is in series also. The diagram shows the capacitors above the supply and the larger capacitance capacitor to the left. The names of the plates of the capacitors from left to right are as follows, A,B,C and D. the + end of the supply is on the left,

i) describe and justify the direction of electron flow when the switch is closed

ii) work out the total capacitance of the arrangement

iii) deduce the charges on each plate when the switch has been closed for some time. justify your answers.

iv) if a 1 megaohm resistor was placed between B and C, how would this affect your answers to i and ii

2. Relevant equations

The Attempt at a Solution


Part i) as the supply establishes a negative potential at end D and a positive at end A, the electrons are moved anticlockwise so as to establish a negative charge at D.

ii) was fine

iii) i think this is where my knowledge of capacitors is strained.
i thought that all the charge moved from A to D. and since the electrons in between B and C are iscolated there isn't a change. This is really where i need help.

iv) naturally my inability to answer the previous part pays no dividends here.

Help would be appreciated.
 
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Jamessamuel said:

Homework Statement


A 12V DC supply is connected in series to 2 capacitors, of 12 and 4 micro farads. A switch is in series also. The diagram shows the capacitors above the supply and the larger capacitance capacitor to the left. The names of the plates of the capacitors from left to right are as follows, A,B,C and D. the + end of the supply is on the left,

i) describe and justify the direction of electron flow when the switch is closed

ii) work out the total capacitance of the arrangement

iii) deduce the charges on each plate when the switch has been closed for some time. justify your answers.

iv) if a 1 megaohm resistor was placed between B and C, how would this affect your answers to i and ii

2. Relevant equations

The Attempt at a Solution


Part i) as the supply establishes a negative potential at end D and a positive at end A, the electrons are moved anticlockwise so as to establish a negative charge at D.

ii) was fine

iii) i think this is where my knowledge of capacitors is strained.
i thought that all the charge moved from A to D. and since the electrons in between B and C are isolated there isn't a change. This is really where i need help.

iv) naturally my inability to answer the previous part pays no dividends here.

Help would be appreciated.
Part (i) may need additional work together with answering part (iii).

What effect will be the effect on plate C, from all that negative charge on plate D ?

Similarly, What will be the effect on plate B from charge on plate A? Is there charge on plate A ?
 
And here's my two cents:

(ii) fine is a relative qualification. Wat came out ?
(iii) Look under 2. relevant equations :rolleyes:.

In fact, how can you have found (ii) without a relevant equation ? And that very equation was derived (in your notes, or your textbook) on a basis that includes solving (iii)

(iv) can be answered without having solved (i), (ii) or (iii)
 
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