Dale
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Be careful here. A geodesic is a local minimum, meaning that it is shorter than any possible path that deviates by an infinitesimal amount. When you are comparing paths that deviate by large amounts then it is possible for a non-geodesic path to be shorter than a geodesic path.Hoku said:Wouldn't this depend on two things, one being the path the artifically accelerated observer took and the second being the point in spacetime where they met up again? Let's use a whirlpool to represent curved spacetime. Let's say the inertial observer (A) and the accelerated observer (B) intend to meet up at 90 deg. from where they started. The inertial observer travels around the whirlpool along his geodesic but (B) has two travel options; he can either go out from the center of the whirlpool, making a big loop or take a "shortcut" by cutting through the inside of the whirlpool. If (B) takes the shortcut, he would have to go slower than (A) and his clock would show a lesser elapsed time because he was closer to the center of the whirlpool. However, if (B) took a loop away from the center of whirlpool he'd have to go faster and his clock would show a greater elapsed time because he was farther from the center.
E.g. consider geodesics between two points on a sphere, there are generally two geodesics which connect the two points, both are great arcs but one is much longer than the other. There are non-geodesic paths which are shorter than the larger of the two geodesics (but no non-geodesic path is shorter than the short geodesic).