How Do I Adjust a Formula to Alternate Sequence Terms?

whatlifeforme
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Homework Statement


I am trying to solve this problem and need help with one aspect.

Homework Equations


sequence: 0,-1,0,1 -- repeated.

The Attempt at a Solution


How do I make every 4th term of the sequence a negative number?

for instance i have: (1 + (-1)^n)/2 but i don't know how to alternative the -1 term in.
 
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whatlifeforme said:

Homework Statement


I am trying to solve this problem and need help with one aspect.

Homework Equations


sequence: 0,-1,0,1 -- repeated.

The Attempt at a Solution


How do I make every 4th term of the sequence a negative number?

for instance i have: (1 + (-1)^n)/2 but i don't know how to alternative the -1 term in.
What functions are you willing to use.

This can easily be done with sine or cosine .

You can probably come up with some solution using the "mod" function.
 
please explain how i would implement cosine or sine.
 
Try sin (n*pi/2) and add integer constants to n to shift the series.
 
then you are going 1, 0, -1, 0. (so if i put sin(pi/2 + npi/2) into the ratio, then i multiply by negative 1 the correct number of times, but what about the zeros? sinx=0 ---> v(sinx) = 0
 
whatlifeforme said:
then you are going 1, 0, -1, 0. (so if i put sin(pi/2 + npi/2) into the ratio, then i multiply by negative 1 the correct number of times, but what about the zeros? sinx=0 ---> v(sinx) = 0
So, it appears you're starting with n = 1 .

Why is it that you say that \displaystyle \ -\,\sin\left(\frac{\pi}{2}+\frac{n\pi}{2}\right)\ doesn't work ?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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