How do I assign Greek indices in Jaxo Draw for scientific diagrams?

  • Thread starter Thread starter Neitrino
  • Start date Start date
  • Tags Tags
    Diagrams
Neitrino
Messages
133
Reaction score
0
Dear PF,
I am trying to draw some diagrams in jaxo draw, but I don't know how to assign Greek index whenever necessary, can you please advise me step by step... as i understand it is related to some "postscript" issues that i don't know how to set up ... would you be so kind and drop me a couple of lines...

thank you...
 
Physics news on Phys.org
I use Jaxo occasionally. For greek indices you need to use the TeX boxes. ("Draw a LaTeX text").

Then you place it (Youll probably have to rearrange it as it draws the text off a little).

Then in the box you type what you want, greek indices are done as in LaTeX such as:

- i e Q_{\ell} \gamma^{\mu}

for <br /> - i e Q \gamma^{\mu}

Now that we have that you have to decide how you want it to display. For papers, I tried to do it as a (Export) LaTex-> EPS . This draws the tex into the eps rather than a separate LaTeX file.

One you have the .eps you can put it in your paper/etc.

If you need a viewer/etc get one here http://pages.cs.wisc.edu/~ghost/index.htm


Or is your problem more complicated?
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Replies
11
Views
682
Replies
15
Views
2K
Replies
15
Views
3K
Replies
8
Views
2K
Replies
12
Views
3K
Replies
1
Views
622
Replies
3
Views
2K
Back
Top