How do I attemp such a Question?

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A student seeks help with a physics problem involving a folded string that transmits power. The discussion revolves around how folding the string affects its properties, including tension, length, mass per unit length, and ultimately power transmission. Participants suggest that while the tension remains constant, the length is halved and mass per unit length doubles, but emphasize that the approach to the problem may be overly complicated. The key point is to consider the implications of using two separate strings versus a single doubled string for power transmission. The conversation highlights the importance of simplifying the problem and focusing on the fundamental effects of doubling the string.
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:confused: Can someone please help me?

A horizontal string can transmit a maximum power (without breaking) if a wave with amplitude A and angular frequency is traveling along it. To increase this maximum power, a student folds the string and uses this "double string" as a medium. Determine the maximum power that can be transmitted along the "double string" assuming that the tension is constant.
 
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You should really show some of your own work and ideas before asking a question in the homework section but I'll give you a hint: While the tension remains the same, both the length and the mass per unit length change. :)
 
If the string is being folded would its mass per unit length double and its length would decause by 1/2?
 
Hi, I need the help with the same problem,

Well I know that Power is equal to P = 1/2 (u)(w)^2(A)^2(v). And when string is doubled the tension stays the same and length is reduced by half and the mass per unit length is increased by two. So the new equation becomes: P = 1/4(u)(w)^2(A)^2(v). Is this a right answer? Or should I have done it somehow differently? Does v changes as well or stays the same?

Thanks
 
well..

That's wrong.. replace v by another equation and start from there.. the rest will just follow through.. Isn't your assignment due today at 1?
 
is due at 1pm or 9am?

Anyway what I got when string is doubled is

aplitude = A/2
Mass per unit length = 2u
speed =(T/2u)= 2^-0.5 v
angular frequence =2pi/9T/2) = 4pi/T = 4pi f
period = T/2
tension =4
P 1/2 (2u) (2pi f)^2 (A/2)^2 (2^-0.5 v) = u 16 (pi f)^2 (1/4) A^2(2^-0.5 v) = (2^-0.5)( u)(w^2)(A^2)(v)
 
you are making your life complicated... this question is doable according to your prof. You are thinking too hard.. it's a really simple question. you are messing with too many variables. just think about what the doubling is affecting.. sorry I cannot help.. I have class to get to.
 
ilovephysicssomuch said:
you are making your life complicated...
I agree. I don't think the half-length thing is part of the solution. The important thing is that the string is *doubled*. Hint -- is there a difference between doubling the string and running two separate strings? Unless you braid the two strings or something, I would think not. And if not, then how much more power can you transmit using two separate strings...?
 
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