How Do I Calculate Coulomb's Law for Fractional Electrical Charges?

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To calculate Coulomb's Law for fractional electrical charges, the fractional value can be directly used in the formula F = K * (qa * qb / r^2). If the charge is +2/3, it should be plugged in as 2/3 in the q's spot. The unit of charge is Coulombs, and for two charges of +2/3 C, the calculation would be F = (8.98e9)(2/3)^2 / r^2. Understanding the relationship between fractional charges and their representation in Coulombs is crucial for accurate calculations.
robertroman10
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The law I am talking about is F=K* (qa*qb / r2) I know the values of all but I have a question on the q's which represent the electrical charges...
If the charge is +2/3 do I plug in the fraction 2/3 in the q's spot? is this the numerical number I use? PLEASE HELP!
 
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robertroman10 said:
The law I am talking about is F=K* (qa*qb / r2) I know the values of all but I have a question on the q's which represent the electrical charges...
If the charge is +2/3 do I plug in the fraction 2/3 in the q's spot? is this the numerical number I use? PLEASE HELP!
Are you trying to find the coulomb force between two charges of +2e/3?

AM
 
Yess
 
OK, so what unit is charge measured in? How much is e in those units? So how much then is 2/3e?
 
robertroman10 said:
The law I am talking about is F=K* (qa*qb / r2) I know the values of all but I have a question on the q's which represent the electrical charges...
If the charge is +2/3 do I plug in the fraction 2/3 in the q's spot? is this the numerical number I use? PLEASE HELP!

If both of the charges are +2/3 C, then you just plug in the charges for q

F = KQQ / R^2
F = (8.98e9)(2/3)^2 / R^2

The units for charge are Coulombs.
 
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ok thanks
 

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