How Do I Calculate My Internet Speeds at Home and Abroad with a 4:1 Ratio?

  • Thread starter Thread starter ramguru
  • Start date Start date
  • Tags Tags
    Complex Figure
ramguru
Messages
2
Reaction score
0
I have one big headache that is connected to math. So the problem is about internet speed. Let's say it's 256_kbps. My internet provider says that the speed agrees with proportion 4:1 (my_country:abroad). Please help me to figure out my final speed in my country (in kbps) and abroad. There are many thoughts, but what is the most correct. Thanks...
 
Mathematics news on Phys.org
"The internet speed" is 256 kpbs where? In Lithuania? Suppose then that the internet speed "abroad" is x. Then 256/x = 4/1, which gives x = 64 kbps.

If "the internet speed" is 256 kpbs abroad, and the speed in Lithuania is y, then y/256 = 4/1, which gives y = 1024 kpbs.
 
It wouldn't be so complex if I knew your question.
 
ramguru said:
I have one big headache that is connected to math. So the problem is about internet speed. Let's say it's 256_kbps. My internet provider says that the speed agrees with proportion 4:1 (my_country:abroad). Please help me to figure out my final speed in my country (in kbps) and abroad. There are many thoughts, but what is the most correct. Thanks...

You have a proportion of "my_country: abroad= 4:1" and assert that "it's 256_kbps". Okay what is IT? Is that the speed in "my_country" or is it the speed in "abroad". You CAN'T use a proportion like that to find BOTH!
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top