How Do I Calculate Position and Velocity in a Particle Movement Problem?

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To calculate the position of a particle moving according to the function s(t) = (1/3)t^3 - t^2 - 4t, simply substitute the values of t into the function. For t=1 and t=6, evaluate s(1) and s(6) directly. The velocity of the particle is found by taking the derivative of the position function, denoted as s'(t). After determining s'(t), substitute the desired t values to find the velocity at those points. This approach effectively addresses both position and velocity calculations for the particle's movement.
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The following code was used to generate this LaTeX image:
A particle moves according to the position function.


s(t) = \frac{1}{3}t^3 - t^2-4t

Find the position of the particle at t=1 and t=6.

To do this, Do i take s'(t) and then plug in the values for t?
then another part is to find the velocity of the particle at t...for that would i use the velocity function, finding the limit of t? I hope someone can help, thanks a lot!
 
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ziddy83 said:
The following code was used to generate this LaTeX image:
A particle moves according to the position function.


s(t) = \frac{1}{3}t^3 - t^2-4t

Find the position of the particle at t=1 and t=6.

To do this, Do i take s'(t) and then plug in the values for t?
then another part is to find the velocity of the particle at t...for that would i use the velocity function, finding the limit of t? I hope someone can help, thanks a lot!

This is extremely simple: You are given the position, you only need to plug in the values for t!

The velocity is the derivative of position with respect time. Determine s' and plug in t.

ehild
 
wow...thanks a lot man
 
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