How Do I Calculate Probability Amplitudes for a Perturbed Quantum State?

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The discussion revolves around calculating probability amplitudes for a perturbed quantum state of a harmonic oscillator, specifically transitioning from state n=2 under a given perturbation. The perturbation involves outer products of state vectors, which can be confusing for those with an engineering background. Participants emphasize the importance of manipulating these outer products formally and applying distributive rules while noting that the commutative rule applies only to scalars. Clarifications about the orthogonality of state vectors are also discussed, particularly regarding the inner products of eigenstates of a Hermitian operator. Understanding these concepts is crucial for accurately computing probability amplitudes in quantum mechanics.
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For my homework, I have a problem in which a (harmonic oscillator) system is prepared in state n=2 for t<0.

For time t>0, there is a perturbation given by

V(t) = sqrt(3/4)*h_bar*omega* (|2><1| + |1><2|)

After this I need to compute the probability amplitudes. However, my background is in engineering, so I'm unsure how to work with these outer products of two state vectors, or even how this mixing works. If anyone has any hints or links on how to work with these, I would appreciate it very much.

Also, for future reference, do these forums automatically generate LaTeX, or do you import the LaTeX equations I've seen in other posts?
 
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In these forums, you can get the $ ... $ environment by using the [ itex ] ... [ /itex] tags. And you can get the \[ ... \] environment with the [ tex ] ... [ /tex ] tags. (Remove the spaces to use those tags) (note the direction of the slash)
 
As to doing the algebra, just manipulate it formally. If you were faced with the product of |1><2| with |2>, that's given by |1><2|2> = |1>. Just remember that the distributive rules work (i.e. (A+B)C = AC + BC), but the commutative rule only works for scalars (i.e. for most S and T: ST \neq TS, but rS = Sr)
 
Hurkyl said:
As to doing the algebra, just manipulate it formally. If you were faced with the product of |1><2| with |2>, that's given by |1><2|2> = |1>. Just remember that the distributive rules work (i.e. (A+B)C = AC + BC), but the commutative rule only works for scalars (i.e. for most S and T: ST \neq TS, but rS = Sr)

Thanks!

Since these are state vectors, would

(|2><1| + |1><2|) * |2>) = |2><1|2> + |1><2|2> = |1> ?

I believe these state vectors are orthogonal, so the <1|2> term is 0, but my textbooks isn't very clear.
 
Here's a useful little calculation: suppose that v and w are eigenstates of a hermetian operator T, with different associated eigenvalues. Then, compute:

\langle v | T | w \rangle

and

\langle w | T | v \rangle

Since these two expressions are complex conjugates of each other, it tells you something about \langle v | w \rangle = \langle w | v \rangle^*.
 
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