How do I calculate the luminosity of a Random Beanbag Machine?

  • Thread starter Thread starter Adrian1234
  • Start date Start date
  • Tags Tags
    Luminosity
AI Thread Summary
To calculate the luminosity of the Random Beanbag Machine, the area of 11 ft² and the rate of 660 beanbags dropping per second are key factors. The initial calculation of 660 beanbags divided by the area yields 60 beanbags per square foot per second, but this does not align with standard luminosity units. Clarification is needed on what "b" represents in the context of luminosity. The discussion highlights confusion regarding the appropriate units and the correct application of the luminosity equation. Accurate calculations require a clear understanding of both the physical context and the relevant equations.
Adrian1234

Homework Statement


A big drunken alumni tailgate game has an area of 11 ft2. Engineering alumni have constructed a Random Beanbag Machine that uniformly drops beanbags on the surface so that in each second 660 beanbags drop randomly all over the surface. The beanbag luminosity of this machine is

(Value)(Units)

Homework Equations


Luminosity equation? Energy Conservation?

The Attempt at a Solution


I thought it would be just 660/11= 60 b/ft2, but I'm not sure,
 
Physics news on Phys.org
What is b?

The units don't fit to a luminosity.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top