How do I calculate the torque needed to turn a one tonne box 360 degrees?

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To calculate the torque needed to turn a one-tonne box 360 degrees around a pivot with a 1-meter diameter, it is essential to consider the effects of gravity and the box's dimensions. The torque required will peak at 90 degrees due to gravitational forces acting on the box. Additionally, if the box starts from a stationary position, extra torque is necessary to accelerate it, which depends on the desired rotational speed and the maximum acceleration point during the rotation. The moment of inertia of the box also plays a crucial role in determining the total torque needed. Overall, the question requires more specific details to provide an accurate calculation.
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If the big grey box is one tonne, and the pivot, the small white circle has a diameter of 1 meter, how do I calculate the torque needed to turn it 360 degrees? Do i just use T=FD? but then I don't have the acceleration.
 

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If there's no gravity any torque, no matter how small, would work. If there is gravity, then the applied torque must be sufficient to overcome whatever torque gravity might be applying as the box moves.
 
The question cannot be answered as posed.

Two things to consider...

If there is gravity acting downwards the static torque required will be at a max when the thing has turned 90 degrees. You need to know the dimensions of the grey rectangle to calculate that.

Does it start from a stationary position? If so additional torque is required to accelerate it. How fast must it rotate? At what point in the rotation will the acceleration be at a maximum? Look up moment of inertia.
 

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