How do I carry out an approximation for this equation?(if L Ns then what?)

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The discussion focuses on approximating the equation \(\frac{Ns-L}{L+Ns}\) under the condition where \(L << Ns\). The user seeks clarification on how to simplify this expression without setting \(L\) to zero, as it is part of a logarithmic function. A solution is provided, suggesting the transformation of the equation to \(\frac{1 - L/N_s}{1 + L/N_s}\) and applying the Binomial theorem to \((1 + L/N_s)^{-1}\) for further simplification.

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\frac{Ns-L}{L+Ns}

What does that reduce to if L << Ns ? Obviously setting L to zero leads me nowhere since that argument above is actually inside a logarithm. I don't know how to perform the approximation. And the answer can't be zero by the way. Is there something I can do here? Usually the only approximations I've done before are just expansions but this is already expanded.

Thank you.
 
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You can write it as
$$\frac{1 - L/N_s}{1 + L/N_s}$$
and then use the Binomial theorem on ##(1 + L/N_s)^{-1}##.
 

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