How do I compute magnetic flux?

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To compute magnetic flux in a rotating circular loop within a magnetic field, the magnetic flux (φ) is defined as the product of the magnetic field (B), the area (A), and the cosine of the angle (θ) between the magnetic field and the normal to the loop's surface. The area can be expressed as A = π * r² * cos(θ), where r is the radius of the loop. To find the induced electromotive force (emf), Faraday's law states that emf (e) equals the negative rate of change of magnetic flux over time, given by e = -dφ/dt. This involves differentiating the magnetic flux expression with respect to time, incorporating the angle's rate of change. The discussion emphasizes the importance of formulating the area and flux correctly to solve for the induced emf effectively.
austin007
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A circular loop (with a radius of 10 cm) rotattes in a constant magnetic fiels, which has a magnitude of 1 T. At an instant when the angle between the magnetic field and the normal axis (to the plane of the loop) is equal to 10 degrees and is increasing at a rate of 20 degrees/s, what is the magnitude of the induced emf in the loop?

How do I compute magnetic flux? ( I know that farady's law can be used to find emf)
 
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Firstly, what do you understand by "magnetic flux"?
 


Fightfish said:
Firstly, what do you understand by "magnetic flux"?

It is the product of magnetic field, B and perpendicular surface area to B, A.

I know B which is 1 T, how do I get A especially the angle.
 


Consider the projection of the surface area of the loop onto the plane perpendicular to the magnetic field (sort of like the 'shadow'). (You can consider the loop in 2D - a straight line to simplify the analysis)
 


Fightfish said:
Consider the projection of the surface area of the loop onto the plane perpendicular to the magnetic field (sort of like the 'shadow'). (You can consider the loop in 2D - a straight line to simplify the analysis)

So is A = pi * r * r cos(10 deg + 20 deg * t) correct?
 


austin007 said:
So is A = pi * r * r cos(10 deg + 20 deg * t) correct?
That would be the correct A (perpendicular) for any time t if the rate of increase remains constant over time. However, it would not help you solve the problem. You should formulate it in a generic fashion: A = pi * r * r cos (theta), solve for dA/dt, before substituting the relevant values into obtain the solution at that point.
 


austin007 said:
So is A = pi * r * r cos(10 deg + 20 deg * t) correct?
At any instant the magnetic flux φ = B*A*cosθ.
So induced emf e = - dφ/dt = -(-B*A*sinθ*dθ/dt )
 
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