How do I convert from kJ/kg to kJ/mol?

AI Thread Summary
To convert the heat of combustion of isobutanol from kJ/kg to kJ/mol, first note that the heat of combustion is 35.981 kJ per gram. Since the molar mass of isobutanol is 74 g/mol, the total heat of combustion for one mole can be calculated by multiplying 35.981 kJ by 74. This results in a heat of combustion of approximately 2663.634 kJ/mol. The conversion process is straightforward, as it simply involves scaling the per gram value by the molar mass. This method effectively allows for the conversion from kJ/kg to kJ/mol.
charlotteyip
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I have researched that isobutanol has a heat of combustion of 35981 kJ/kg; however I need this to be in kJ/mol. From calculations, the molar mass of isobutanol was found to be 74g/mol. How would I go about in converting this?

Relevant equations (?)
#mols=mass/molarmass

But how can I use this?
 
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74g/mol
What is the heat of combustion of one gram?

35.981 kJ per gram
You get 35.981 kJ when you burn one gram, and a mole is 74 grams.
So wouldn't burning a mole just give you 74 times as much as burning one gram?

What is 35.981 multiplied by 74?
 
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marcus said:
74g/mol
What is the heat of combustion of one gram?

35.981 kJ per gram
You get 35.981 kJ when you burn one gram, and a mole is 74 grams.
So wouldn't burning a mole just give you 74 times as much as burning one gram?

What is 35.981 multiplied by 74?
Thanks! I get it now :)
 

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