How do I evaluate this log expression?

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To evaluate the expression 5^(log_5(10) - 1), one can utilize the properties of exponents and logarithms. The expression can be rewritten using the identity 5^(a + b) = 5^a * 5^b, allowing for simplification. Alternatively, converting the constant 1 into a logarithmic form facilitates combining the logarithmic terms. Understanding that exponentials and logarithms are inverse functions is crucial in this process. Reviewing logarithmic properties can further aid in solving the expression effectively.
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Homework Statement


5^(log510-1)

Homework Equations


n/a

The Attempt at a Solution


I have no idea how to approach this.
 
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Well, you know what

5^{\log_5(x)}
is, don't you?

Then there are two ways to solve the question: you can split the sum in the power to a multiplication:
5^{a + b} = 5^a \cdot 5^b

or you can first write 1 as a logarithm (base 5), then combine the two logarithms into one.
 
Do you know that exponentials and logarithms are inverses of each other?
y = ax \Longrightarrow x = logay
Then, after substituting the x, y = a^{\log_a y}
So what is 5^{\log_5 x} ?

Perhaps you should review http://en.wikipedia.org/wiki/Logarithm" .
 
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I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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