How do I find the inertia tensor for a triangle with a given density function?

Keplini
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Homework Statement


Find the center of mass and inertia tensor at the CoM of the following triangle. Density of the triangle is \sigma(x,y) = x and y=3-3/4x .

Homework Equations


Find the inertia tensor at the origin (x,y,z) and apply the parallel axis theorem

I_{ij}=\intdV(\delta^{ij}\vec{x}^{2}-x^{i}x^{j})


The Attempt at a Solution


I've been able to find the mass (which gave me 8 -correct me if I'm wrong-), the CoM and now I'm trying to find the inertia tensor. For the first component, I get something like:

I_{xx}=\int^{4}_{0}\int^{3-3/4x}_{0} xy^2 dx dy

which gives me something like

I_{xx}=\int^{4}_{0}x\frac{(3-3/4x^)^{3}}{3}dx

which looks like a big monster and I don't feel like integrating that ! ;) Basically, I believe it's getting way too complicated to be the good answer. Any help on finding that inertia tensor would be greatly appreciated !

Thanks,
Kep
 

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Hi, i need help on the same problem. So if anyone can help it would be great. By the way, Keplini, which book is this problem from?
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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