How do I find the phase difference between two oscillators

AI Thread Summary
To find the phase difference between two harmonic oscillators at time t=1, start by recalling the definition of "phase" in simple harmonic motion. The oscillators are given as x(t)= 0.4 cos(2.1t) and x(t)= 0.4 cos((π/2)t + π). By substituting t=1 into both equations, the phase values can be calculated. The phase difference is determined by subtracting the two results. This approach effectively leads to the solution.
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Homework Statement



Find the phase difference between two harmonic oscillators at time t=1

Homework Equations


I've already found x(t)= .4 cos(2.1t) and x(t)= .4cos((pi/2)t + pi)


The Attempt at a Solution


I don't really know where to begin
 
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Hello, and welcome to PF!

Start with recalling (or finding) the definition of the word "phase" for simple harmonic motion.
 
Hey thanks! :)

Oh wow...Okay now I got it. Just plug in 1 for t and subtract the two terms in the parentheses. Thanks for the lead!
 

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