How Do I Find Vector Components Using Trigonometric Formulas?

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To find vector components using trigonometric formulas, one can assign an angle, such as θ_0, to the initial velocity, which has both vertical and horizontal components. The relevant trigonometric equations include sin = o/h, cos = a/h, and tan = o/a. When solving for θ_0, two solutions will typically emerge, restricted to angles between 0 and 90 degrees. The discussion touches on the mathematical nature of sine values and the intuitive reasoning behind having two angles for a given range. Understanding these concepts is crucial for accurately determining vector components in physics problems.
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Vector Angle Problem - Answered, thanks! =)

1. The problem statement

Find Vector Components

Homework Equations



trig formulas are important here: sin =o/h, cos=a/h, tan=o/a

The Attempt at a Solution



Thanks for the help! =)
 
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meganw said:
Is 7.6 the initial vertical velocity? Or horizontal? Sorry I'm just confused.

It's just initial velocity, which has both vertical and horizontal components.
 
But how do I find those components if I don't know the angle?
 
Just assign the angle some name, like \theta_0. Then with the given info and the equations of motion, solve for \theta_0.
 
Thank you so much!
 
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meganw said:
Thank you so much! I didn't realize I could do that sort of thing...thanks again! =)

Is there any "physics" reason why there are 2 angles...mathematically sin x = 1.5 at various values of x...

sin x must be between 0 and 1...

Actually there's one way to think about why there are two angles... Think about the range when the angle is 0 and the angle is 90... in both cases the range is 0. so the range gets larger as you go up from 0... and as you go down from 90... so that gives an intuitive reason why there are two angles for each range... for a particular range... if you have an angle close to 0... then there's another angle close to 90...

When you solve for \theta_0 two solutions will appear... note: you're restricted to angles between 0 and 90.
 
meganw said:
Is there any "physics" reason why there are 2 angles...mathematically sin x = 1.5 at various values of x...

I do not know the "physical reason" behind it. But since we are talking about angles and distances, I guess I will resort to saying "the math works that way." :)
 
Wow, thanks both of you! I really appreciate it, you have no idea! =)
 
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