How do i integrate this "e^[−(x/xa)]

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how do i integrate this "e^[−(x/xa)]
 
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Does xa mean x*a, or is it a variable different from x?
 


Errr... Do you mean e^{\frac{x}{xa}} ? If so just cancel the x. You also need to show some working out and should have a more discriptive title. We are here to help not to do homework.
 


On the other hand if you mean xa, some fixed (constant) value, then use the substitution u= x/xa.
 


i meant x subscript a. but i figured out the answer. and fyi this is not my homework. I am studying for my physics test. but thanks for being rude...
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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