- #1
Dell
- 590
- 0
How do i solve the following with or without use of logs?
3^x=x^2
the problem being that i have x both in my exp and in my base, what i have done is taken each side and gotten
(3^x)^(1/x)=(x^2)^(1/x)
3=x^(2/x)
3^(1/2)=(x^(2/x))^(1/2)
sqrt(3)=x^(1/x)
0.5*ln(3)=(1/x)*ln(x)
3^x=x^2
the problem being that i have x both in my exp and in my base, what i have done is taken each side and gotten
(3^x)^(1/x)=(x^2)^(1/x)
3=x^(2/x)
3^(1/2)=(x^(2/x))^(1/2)
sqrt(3)=x^(1/x)
0.5*ln(3)=(1/x)*ln(x)