How do i solve this physics problem that contains vectors

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SUMMARY

The discussion focuses on solving a physics problem involving vector addition and subtraction with two displacement vectors, A and B, each having a magnitude of 3.00. Vector A is positioned at a 30-degree angle from the positive X-axis, while Vector B lies along the Y-axis. The key to solving the problem is to decompose the vectors into their components, using the equations \(\vec{B}=3\hat{y}\) and \(\vec{A}=3\cos{30}\hat{x} + 3\sin{30}\hat{y}\). This method allows for the calculation of the resultant vectors for operations A+B, A-B, B-A, and A-2B.

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  • Knowledge of vector addition and subtraction principles
  • Ability to perform calculations involving angles in degrees
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  • Explore graphical methods for vector addition and subtraction
  • Study the effects of changing angles on vector magnitudes and directions
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Homework Statement


Each of the displacement vectors A and B have a magnitude of 3.00.
Vector B lies on the y-axis and Vector A has a 30 degree angle from the positive X axis.

a) A+B
magnitude = ?
θ = ?

(b) A-B
magnitude = ?
θ= ? °

(c) B - A
magnitude =?
θ= ? °

(d) A - 2B
magnitude =?
θ= ? °


Homework Equations





The Attempt at a Solution



I really don't have a clue how to figure this out, any help would be great
 
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The idea is, when adding vectors, to separate them into their components, and then add those components to make the new vector. You know [tex]\vec{B}=3\hat{y}[/tex], and [tex]\vec{A}=3\cos{30}\hat{x} + 3\sin{30}\hat{y}[/tex], at least you should know that. So then, for example, [tex]A + B = 3\cos{30}\hat{x} + (3 + 3\sin{30})\hat{y}[/tex]. Make sense? See where you can get using this method.
 

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