How Do Newton's Third Law and Force Calculations Apply to Hockey Players on Ice?

AI Thread Summary
Newton's Third Law states that for every action, there is an equal and opposite reaction, which applies to the forces between two hockey players on ice. Player A, weighing 100kg, pushes Player B with a force of 40N, while Player B, weighing 112kg, pushes back with 50N. The net forces acting on each player are 90N in opposite directions when considering their respective weights and the forces applied. Consequently, Player A experiences an acceleration of 0.9 m/s², and Player B experiences an acceleration of 0.8 m/s². The discussion highlights the importance of understanding how forces interact and the implications of mass on acceleration in this context.
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Homework Statement



two hockey players are standing on ice. Player A is 100kg and player B is 112kg, Player A pushes B with 40N and player B pushes A with 50N.

what are the action/reaction forces?
what are the accelerations?

Homework Equations



F = ma

The Attempt at a Solution



player A has a force of 50N on him plus the reaction from his own force of 40N making 90N left

90N on each player in opposite directions, 90/100 = 0.9 m/s^2 and 90 /112 = 0.8 m/s ^2 in other direcctionPlease help me!
 
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VidsEpic said:

Homework Statement



two hockey players are standing on ice. Player A is 100kg and player B is 112kg, Player A pushes B with 40N and player B pushes A with 50N.

what are the action/reaction forces?
what are the accelerations?


Homework Equations



F = ma


The Attempt at a Solution



player A has a force of 50N on him plus the reaction from his own force of 40N making 90N left

90N on each player in opposite directions, 90/100 = 0.9 m/s^2 and 90 /112 = 0.8 m/s ^2 in other direcction


Please help me!
Looks fine.
Where do you need help?
 
Is this correct?
 
The diagram looks like this:http://i.imgur.com/LP6NfNw.jpgsome people are telling me that it is 10N left on the 100kg object?

Is it correct that I consider on each object the force of its own reaction + the force applied to it so that on 100kg I have 90N left and on 112kg I have 90N right?
 
VidsEpic said:
Is it correct that I consider on each object the force of its own reaction + the force applied to it so that on 100kg I have 90N left and on 112kg I have 90N right?
I would interpret the problem statement in that way, yes.

Please don't write PMs related to homework threads, they are just annoying.
 
VidsEpic said:

Homework Statement



two hockey players are standing on ice. Player A is 100kg and player B is 112kg, Player A pushes B with 40N and player B pushes A with 50N.
This is a poor question, in my view. What does it mean that A applies 40 N of force to B and B applies 50 N to A? How? They will always apply the same magnitude of force to each other - even if one pushes harder than the other.

AM
 
The players are extended bodies, and push each other at different points. See picture.

ehild
 

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ehild said:
The players are extended bodies, and push each other at different points. See picture.

ehild
Ok. But that does not mean that they push each other with different magnitudes of force.

An astronaut in space may push off with his legs against one end of the spaceship with 100 N force. But that does not mean that the spaceship applies 0 force to the astronaut. On the contrary, the spaceship applies 100N of force to the astronaut. There is no difference between "apply" and "push" here.

AM
 
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