How Do Ships A and B Move Relative to Each Other?

AI Thread Summary
Two ships, A and B, depart simultaneously, with A traveling northwest at 19 knots and B at 28 knots, 40° west of south. The relative velocity of ship A to B is calculated to be 35.181 knots, with the direction needing to be expressed as degrees east of north. A participant initially miscalculated the angle but corrected it by subtracting from 90 degrees to find the accurate direction. For determining the bearing of ship B relative to A, a diagram is recommended instead of simply adding 180 degrees to the previous angle. The discussion emphasizes the importance of correctly interpreting directional measurements in navigation.
Dante Tufano
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Two ships, A and B, leave port at the same time. Ship A travels northwest at 19 knots and ship B travels at 28 knots in a direction 40° west of south. (1 knot = 1 nautical mile per hour; see Appendix D.)
(a) What is the magnitude the velocity of ship A relative to B?
35.181 knots

(b) What is the direction of the velocity of ship A relative to B?
_____ ° east of north

(c) After what time will the ships be 110 nautical miles apart?
_____ h

(d) What will be the bearing of B (the direction of B's position) relative to A at that time?
_____° west of south


2. Vab = Vas - Vbs
Vas = -19cos45 + 19sin45 = -13.435i + 13.435j
Vbs = -28cos50 - 28sin50 = -17.998i - 21.449j
Vab = 4.563i + 34.884j
magnitude of Vab = 35.181
arctan(34.884/4.563) = 82.548 degrees

3. For some reason, this value for the angle (which I'm trying to find for part b) is wrong. Any ideas on what I did wrong guys?
 
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Some help anybody? Please
 
It looks like the problem wants the angle measured East of North. The arctangent function is giving you the angle measured from the horizontal axis (i.e. East).

So, what do you need to do to find the angle as measured from the vertical axis?
 
Dante Tufano said:
arctan(34.884/4.563) = 82.548 degrees
I didn't confirm your arithmetic, but you need to express your answer as requested: Degrees east of north.
 
Oh, right! Thanks a lot guys, I'll try that out.

Edit: It worked! I subtracted the angle from 90 degrees and it was the correct answer
 
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Now how do I solve part D? I tried adding 180 degrees to the value of the angle for part B, but apparently that's wrong. Any advice?
 
Dante Tufano said:
Now how do I solve part D? I tried adding 180 degrees to the value of the angle for part B, but apparently that's wrong. Any advice?
Why add 180 degrees to the answer for part B? It's perfectly OK to swing the velocity vector by 180 degrees, which is probably what you were thinking. Draw a diagram showing their relative positions, then read off the answer.

Once again, be sure to express your answer as requested: Degrees west of south.
 
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