How do the magnetic fields produce emfs?

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Discussion Overview

The discussion revolves around the relationship between magnetic fields and the electromotive force (emf) generated when a wire is moved through a magnetic field. Participants explore the theoretical underpinnings of this phenomenon, including the work done by external forces and the nature of magnetic forces, as well as implications for understanding electromagnetic induction.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant describes the emf as defined by the integral of forces on charges, questioning how it relates to work done by an external force while the magnetic force does no work.
  • Another participant clarifies that the magnetic force does not perform work because it acts perpendicular to the displacement of charges, suggesting that the energy is supplied by the external force pulling the wire.
  • A follow-up question challenges the notion of the magnetic field producing emf if the energy is provided by the person pulling the wire.
  • Several participants emphasize that pulling a wire through a magnetic field generates an emf, prompting further exploration of the forces acting on charges within the wire.
  • One participant compares the magnetic force to the normal force in mechanics, expressing confusion about how magnetic forces can influence charge movement without doing work.
  • A later reply introduces Faraday's Law and discusses the integral form, suggesting that understanding the need for an external force is crucial since the magnetic field does not do work on charges.
  • Another participant reiterates the analogy with the normal force, emphasizing that while both forces do not do work, they influence the motion of objects in different contexts.
  • One participant encourages deeper reasoning and exploration of the concepts rather than seeking direct answers, highlighting the learning process involved.

Areas of Agreement / Disagreement

Participants express varying interpretations of the role of magnetic forces in generating emf, with some agreeing on the necessity of external work while others question the implications of this relationship. The discussion remains unresolved regarding the conceptual understanding of how magnetic forces influence charge movement without performing work.

Contextual Notes

Participants note the complexity of the relationship between magnetic forces and work, with some assumptions about the nature of forces and their effects on motion remaining unexamined. The discussion also touches on the mathematical formulations of electromagnetic principles without reaching consensus on their implications.

ghostfolk
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I should add context to this question that what I know so far of the emf is that it is defined as ##\mathscr E=\oint f \cdot d\ell## where ##f## is the sum of the forces on the charges. In the textbook I'm reading it gives an example of where a person pulls a rectangular wire with a velocity ##\vec{v}## and the left side of that wire is in a uniform magnetic field.
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After some calculations, the author states that calculating the emf from the current induced in line ##ab## at a particular instant is equivalent to the work done by the person pulling the wire even though the force of the magnetic field, ##\vec{v}\times \vec{B}##, has no effect on the work done by the person and the force exerted by the person, ##f_{pull}## has no effect on the emf. How is that we can interpret the emf as ##\begin{equation} \mathscr E=\int f_{pull} \cdot d\ell=\oint f_{mag} \cdot d\ell\end{equation}##, yet the force produced by a magnetic field does no work?
 
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It is not clear where the problem lies: your post describes how moving a wire in a magnetic field gets you and emf.
The magnetic force does no work because it acts perpendicular to the displacement of the charge.
The work needed to generate the energy in the circuit is provided by whatever is pulling the wire... you can see this if you try dropping a conductor past a magnet.
 
Simon Bridge said:
It is not clear where the problem lies: your post describes how moving a wire in a magnetic field gets you and emf.
The magnetic force does no work because it acts perpendicular to the displacement of the charge.
The work needed to generate the energy in the circuit is provided by whatever is pulling the wire... you can see this if you try dropping a conductor past a magnet.
Then why can say the the magnetic field produces an emf if the one pulling the wire is providing the energy?
 
You get an emf by pulling a wire through a magnetic field.
Work out the forces on a charge in the wire.
 
Simon Bridge said:
You get an emf by pulling a wire through a magnetic field.
Work out the forces on a charge in the wire.
My issue is that I have been thinking of the force produced by the magnetic field as something similar to the normal force in mechanics. Both only affect the way the object's path, but do no work. So it's confusing to me how the magnetic force can push charges around a wire.
 
One more hint: The correct integral form of Faraday's Law is
$$\mathcal{E}=\int_{\partial F} \mathrm{d} \vec{r} \cdot \left (\vec{E}+\frac{\vec{v}}{c} \times \vec{B} \right)=-\frac{\mathrm{d}}{\mathrm{d} t} \int_{F} \mathrm{d}^2 \vec{f} \cdot \vec{B}.$$
Here, ##\vec{v}=\vec{v}(t,\vec{x})## is the velocity of the boundary ##\partial F## of the surface ##F##.

Further you know Ohm's Law, ##\mathcal{E}=R I## if you take the boundary ##\partial F## around the wire. Concerning the signs you just have to remember that the relative orientation of the boundary and the surface should be chosen by the right-hand rule.

Then you should think about the question, why you need a force to pull the circuit also the magnetic field doesn't do work on the charges.
 
My issue is that I have been thinking of the force produced by the magnetic field as something similar to the normal force in mechanics. Both only affect the way the object's path, but do no work. So it's confusing to me how the magnetic force can push charges around a wire.
... well, the normal force (say, from the surface of a ramp) does not push the objects around either, it does no work. The work done pushing something up a ramp is done by the person (or whatever) doing the pushing.

Of course, looking at a ramp, you can intuitively feel how the ramp forces the motion - there's a physical contact between object and ramp. With electromagnetism, you just have this force that seems to come out of nothing. However, your intuition about the ramp is incorrect: the "contact" in question is the same electromagnetism.

If you imagined a charged block constrained to move on a rail, and the rail slides through a magnetic field ... would that help?

Vanhees71 has good focussing questions for you.
Don't worry that nobody is just telling you the answer - this is something that everyone has to wrestle with to some extent and you get more out of it the more you can do for yourself. So, mostly. we are just focussing on your reasoning process.
 

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