How Do Traffic Signal Timings Affect Car Speed Calculations?

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Traffic signal timings significantly influence car speed calculations along a straight road with signals positioned at 0 m, 600 m, and 1200 m. The discussion includes drawing displacement-versus-time curves for cars moving at constant speeds in both directions, emphasizing that the slope of these curves represents speed. The fastest speed corresponds to the steepest slope on the graph, which is crucial for timing through the signals. Additionally, there is confusion regarding the optimal speed for passing all signals in the middle of their green intervals, indicating a need for clarification on this aspect. Understanding the relationship between displacement, time, and speed is essential for solving the posed questions.
brad sue
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Hi,
this is a problem I have . But because I cannot include the graph, I try to do via Microsoft Word. I put it as an attachment. I hope that you will understand it.

This is the problem:

Traffic signals are placed along a straight road at positions x = 0 m, x = 600 m, and x = 1200 m (see graph in attachment)). The time intervals during which the signals are green are shown by the thick lines ( in red) in the figure.

(a) Draw the displacement-versus-time curves (fastest and slowest) for a car that passes through all the lights when the car moves with constant speed.

(b) Draw a similar set of lines for a car traveling in the opposite direction.

(c) Assuming that the lights are timed such that a car passes through all lights in the middle of the time interval, what is the speed for which the lights are timed?

(d) What is the fastest constant speed of a car that makes it through all the signals, assuming it arrives at the first light at the optimal moment?

For info.:
The grah is a 2 dimension space with time(s) on horizontal and the position x(m) in vertical.
The interval are put in red and I mentioned the time interval at the end of each line.
Please help me with that . I do not understand it

Thank you very much.

Brad
 

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Well if you map x=x(t), then v = dx/dt and the slope is speed (or magnitude of velocity).

If you draw a straight line, it's slope will be a constant speed.

So the fastest speed, will have the steepest slope.
 
ok!

Thank you that make more sense now , but what about quesion c

I do not understand this question .
Thanks

Brad
Astronuc said:
Well if you map x=x(t), then v = dx/dt and the slope is speed (or magnitude of velocity).

If you draw a straight line, it's slope will be a constant speed.

So the fastest speed, will have the steepest slope.
 
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