How Do Wave Interference and Velocity Relate in Real-Life Scenarios?

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The discussion centers on wave interference observed by a beach comber, where incoming waves interact with reflected waves from a concrete breaker, creating a standing wave pattern. The oscillation period of the waves is noted as 2.4 seconds, with a distance of 3.2 meters indicating minimal vertical motion. The wavelength is calculated as 12.8 meters, based on the distance to the first node, leading to a wave velocity of approximately 2.7 m/s. Participants clarify that the period is crucial for determining wave speed and wavelength, emphasizing the relationship between these factors in standing wave scenarios. Understanding these concepts is essential for accurately analyzing real-life wave interactions.
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Homework Statement


A beach comber walking along the top of a sea wall notices that the waves reflecting off of the concrete breaker are creating a pattern of interference with the original incoming waves. A few meters from the breaker the waves are at maximum oscillation with a time between peak and trough of 2.4 seconds. Exactly 3.2m further to sea, there is virtually no vertical change in the water's motion. What is the length and velocity of the waves?


Homework Equations



v=fxlamda

The Attempt at a Solution


So I'm not sure if I'm completely misinterpreting this but I'm thinking it forms a standing wave pattern and the first node is 3.2m away from the antinode so 3.2m x 4 = a wavelength of 12.8m and then v=(4.)(12.8m)(1/4.8)= 2.7m/s
Did I do it right or am I completely off?
 
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That sounds reasonable to me.

The distance between max and min is 3.2m ... separation of consecutive maxima is 6.4m.
Which would represent a path difference of a single wavelength.
 
Oh wait. 2.4 s is the period not the frequency.
 
That makes a difference yes ;)
You only need to relate the period of the standing wave oscillations to the speed and wavelength of the two traveling waves that make it.
 
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