How do we convert a summation to integration?

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When converting a summation of the form ∑ x_i y_i to integration, it's crucial to determine whether to use ∫ x dy or ∫ y dx, as they are not equivalent except for linear functions without constant offsets. Integration serves as a more efficient method for calculating areas under curves compared to summation. The discussion highlights that while summation can be seen as an analog to integration, the two processes are fundamentally different, particularly in applications like calculating the center of mass. The distinction is emphasized by the absence of 'delta' in continuous formulas, which implies the use of infinitesimal elements. Understanding these differences is essential for accurate mathematical conversions between summation and integration.
MacNCheese
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When converting a summation of the form

\sum x_i y_i

to integration, how do we know if it's

\int x dy

or

\int y dx

At first I thought they're equivalent but obviously that's only true for a linear function with no constant offset.

I kind of see integration as a better form of multiplication so I've always had trouble with the fact that multiplication is commutative but integration isn't. A little help?
 
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Your description of the summation as an analog of integration is not quite accurate.
∑xiΔyi -> ∫xdy
∑yiΔxi -> ∫ydx
 
Summation is used to find the area under the curve. Integration is same thing, but much faster.
 
Well if you look at something like center of mass, it's mentioned as (in wikipedia)

\frac {\sum m_i r_i} {\sum m_i}

for discrete particles and

\frac {1} {M} \int r dm

for continuous distribution. There's no 'delta' anywhere.
 
Yes, those are two completely different formulas. The first is NOT the Riemann sum leading to the second.
 
MacNCheese said:
Well if you look at something like center of mass, it's mentioned as (in wikipedia)

\frac {\sum m_i r_i} {\sum m_i}

for discrete particles and

\frac {1} {M} \int r dm

for continuous distribution. There's no 'delta' anywhere.
Although the symbol Δ doesn't appear, it is implicit in the meaning of mi which is a small piece of the mass, which sums to M.
 
HallsofIvy said:
Yes, those are two completely different formulas. The first is NOT the Riemann sum leading to the second.

Isn't it? Then how do we derive such an expression?

mathman said:
Although the symbol Δ doesn't appear, it is implicit in the meaning of mi which is a small piece of the mass, which sums to M.

Thanks, that helps.
 
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