What is the Correct Method for Deriving p = γmv?

In summary, the conversation discusses the concept of momentum in different frames of reference, particularly in the context of special relativity. The speaker suggests using the relativistic 4-momentum as a conserved quantity, which is defined by the relativistic action of a point particle. This quantity meets all the criteria for a valid momentum, and has been verified through experiments.
  • #1
physics user1
I thought this mental experiment: consider an inertial frame of reference solidal to a particle moving with velocity v respect to another inertial frame of reference, i got to find the momentum in the second frame of reference (in the first is 0 since is solidal with the particle)

p= m* dx/dt

And then i plug instead of x and t the lorentz tranformation thwt connects them with t' and x'...

But it doesn't work, where am i wrong? Is that method correct? If not why?
 
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  • #2
That doesn't work, because the (spatial component of the!) relativistic momentum is p = ymv to start with. You should transform the 4-momentum. This 4-momentum is defined by the relativistic action of a point particle.
 
  • #3
The idea is to find an expression that:
  • is conserved in closed systems (and additive) even when ##v \rightarrow c##,
  • increases in magnitude without bound as ##v \rightarrow c## (because otherwise it would have a maximum limit like ##v## does, and this would contradict the first criterion), and
  • reduces to ##\mathbf{p} \approx m \mathbf{v}## in the classical limit.
The famous Tolman/Lewis thought experiment demonstrates that if such a quantity exists, then it must be ##\mathbf{p} = \gamma m \mathbf{v}##, which obviously meets the second and third criteria. See here: https://books.google.com/books?id=FrgVDAAAQBAJ&pg=PA76.

As for the first criterion, experiment verifies that this vector is indeed conserved at all possible values of ##v##. (Think particle accelerators.)
 

Related to What is the Correct Method for Deriving p = γmv?

1. How do we derive p = γmv?

The equation p = γmv is derived from the relativistic momentum formula, p = mγv. This formula takes into account the effects of special relativity, such as time dilation and length contraction, when calculating an object's momentum. To derive this equation, we use the Lorentz transformation equations to convert the classical momentum formula, p = mv, into its relativistic counterpart.

2. What is the significance of γ in the equation p = γmv?

The symbol γ, also known as the Lorentz factor, represents the ratio of an object's relativistic mass to its rest mass. It is a crucial factor in the relativistic momentum formula, as it accounts for the increase in an object's mass as it approaches the speed of light. As an object's velocity increases, γ also increases, leading to a larger value for momentum.

3. How does the equation p = γmv differ from the classical momentum formula, p = mv?

The main difference between the two equations is the inclusion of the Lorentz factor, γ, in the relativistic momentum formula. This factor takes into account the effects of special relativity, such as time dilation and length contraction, which are not accounted for in the classical formula. As an object's velocity approaches the speed of light, the difference between the two equations becomes more significant.

4. Can the equation p = γmv be used for all objects?

No, the relativistic momentum formula is only applicable to objects moving at speeds close to the speed of light. For objects moving at slower speeds, the classical momentum formula, p = mv, is sufficient. The Lorentz factor, γ, approaches a value of 1 for objects with low velocities, making the relativistic momentum formula equivalent to the classical formula.

5. How is the equation p = γmv used in real-world applications?

The relativistic momentum formula is used in various fields of science, such as particle physics and astrophysics, to accurately calculate the momentum of high-speed objects. It is also an essential component of other equations, such as the relativistic energy formula, E = γmc². Additionally, it has practical applications in technologies such as particle accelerators and space travel, where objects can reach velocities close to the speed of light.

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