How do we get the n th term of the sequence?

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Homework Statement



how do we get the n th term of a sequence if it is given in form of
##x_{ n+1 }=f({ x }_{ n })##
and the p th term is given

Homework Equations


I figured we may get it if we get it in the form of
##x_{ n+1 }-{ x }_{ n }## but how?can we even get it?if yes,under what conditions?

The Attempt at a Solution


example: n th term of sequence where
##x_{ n+1 }=\frac { { x }_{ n }+\frac { 2 }{ { x }_{ n } } }{ 2 } ##
where ##{ x }_{ 0 }=1##
 
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Non-linear recurrences are unlikely to have solutions in closed form. Iteration is generally the only way to find x_n given x_0.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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