How Do You Build a Wave Transmitter for Destructive Interference?

AI Thread Summary
To build a wave transmitter for sound cancellation similar to noise-cancelling headphones, you need to set up a system comprising a microphone, an inverting audio amplifier, and a speaker. The microphone captures the unwanted sound waves, which are then processed by the amplifier to create a 180-degree phase shift. This inverted audio is sent to the speaker, which emits the sound waves that interfere destructively with the incoming noise. Proper design and guidance are essential for successful implementation. Consulting with an expert can help navigate the process effectively.
a.glick
Messages
4
Reaction score
0
How would I go about building a wave transmitter? Like in the noise cancelling headphones. I want to build a transmitter that absorbs sound waves, reflects them, and then shoots them out creating destructive interference.
 
Physics news on Phys.org
a.glick, Welcome to Physics Forums!

You need to call things by their correct names! In all sciences, using the correct term is the only way to communicate ideas with accuracy.

1. Sound waves are emitted by a transmitter. Example: a speaker
2. Sound waves are received by a receiver. Example: a microphone
3. Audio can be amplified by an amplifier.
4. Sound waves humans can hear is known as "audio"


Noise cancelling headphones receive sound from the local environment. The electrical circuits inside amplify and invert that audio. That is, it is phase shifted 180 degrees. Then that audio is sent to the earphones of the person wearing the headphones. When those waves meet up with the incoming waves they should totally cancel out. This is known as destructive interference, as you said. The result expected is the wearer does not hear any sound from the external enviroment.

So, what you want to build is very similar to noise cancelling headphones, just as you said. You need to design and build a receiver, an inverting amplifier, and a speaker.
 
Last edited:
so essentially i need to attach a microphone to a speaker. what am i supposed to use to create the phase shift of the wave?
thanks for your help bobbywhy.
 
a.glick, Visualize a simplified block diagram with 3 boxes:

1. Microphone
2. Inverting audio amp
3. Speaker

#1 feeds into #2 which feeds into #3.

Use the microphone to detect (receive) the sound you want to eliminate. Feed the output of the microphone into an inverting audio amplifier. Send the output of the amplifier to a speaker. Point the speaker towards the source of the sound. The inverted waves transmitted by the speaker will interfere destructively in midair with the sound waves you want to eliminate. Voila! Sound cancellation!

I suggest you consult with someone who can advise you and guide you through this process. It is not too difficult, but it seems to me you will need some help to make it work.
 
Last edited:
Thread ''splain this hydrostatic paradox in tiny words'
This is (ostensibly) not a trick shot or video*. The scale was balanced before any blue water was added. 550mL of blue water was added to the left side. only 60mL of water needed to be added to the right side to re-balance the scale. Apparently, the scale will balance when the height of the two columns is equal. The left side of the scale only feels the weight of the column above the lower "tail" of the funnel (i.e. 60mL). So where does the weight of the remaining (550-60=) 490mL go...
Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion? In a second scenario, imagine a person with a...
Scalar and vector potentials in Coulomb gauge Assume Coulomb gauge so that $$\nabla \cdot \mathbf{A}=0.\tag{1}$$ The scalar potential ##\phi## is described by Poisson's equation $$\nabla^2 \phi = -\frac{\rho}{\varepsilon_0}\tag{2}$$ which has the instantaneous general solution given by $$\phi(\mathbf{r},t)=\frac{1}{4\pi\varepsilon_0}\int \frac{\rho(\mathbf{r}',t)}{|\mathbf{r}-\mathbf{r}'|}d^3r'.\tag{3}$$ In Coulomb gauge the vector potential ##\mathbf{A}## is given by...
Back
Top