How do you calculate average force?

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To calculate average force, one can use the area under the force versus time graph, which equates to the product of average force and total time. If a graph is unavailable, average force can be determined using the equation F_average = (m(v - u)) / t, where m is mass, v is final velocity, u is initial velocity, and t is time. The average acceleration is calculated as the change in velocity divided by the time taken for that change. It's important to note that average acceleration can be used even if the acceleration is not constant. Understanding these relationships allows for accurate calculations of average force in various scenarios.
Jessibaca
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How do you calculate average force? Where does time fit in?
 
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If you have the graph of the force F as a function of time t, you first need to calculate the area below the graph, which is equal to the product of the average force and the total time:
\int _{t = 0} ^{\Delta t}Fdt = F_{avg}\Delta t

See the attachment for an example. The red graph signfies the average force. The areas below the red graph and the blue graph need to be the same.
 

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Avg F

I don't have a graph. I have initial/final velocity, mass and time. Is there an equation for Average Force?
 
Then the force is constant... first find the acceleration of the body. Use this formula:
V_f = V_0 + at
And then when you have the acceleration and the mass it's easy to find the force:
\Sigma F = ma
 
The force is not necessarily constant Chen, the 'a' (i.e. acceleration) in your first equation is infact the average accelartion (from the data set given it is impossible to deterimne whether a is constant or not).

Chen has alreday given you the correct equations, which can be given as:

F_{average} = \frac{m(v-u)}{t}

where u is the initial velocity and v the final velocity
 
The average force is mass times the average acceleration.

The average acceleration is simply the change in velocity divided by the time it took to change the velocity, regardless of whether the change is smooth or not.
 
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