How Do You Calculate Bullet Speed in a Ballistic Spring System?

AI Thread Summary
To calculate the bullet's speed in a ballistic spring system, one must consider the conservation of energy principles, incorporating kinetic energy, gravitational potential energy, and spring potential energy. The initial kinetic energy of the bullet and the spring's potential energy at maximum compression must equal the final kinetic energy and potential energies. The attempt to derive the expression begins with the equation (1/2)mvi² + (1/2)kxi² = (1/2)mvf² + (1/2)kxf², simplifying under the assumption that initial gravitational potential energy is zero. The challenge lies in properly integrating the mass of the block (M) and the gravitational force (g) into the calculations. Ultimately, a correct expression for the bullet's speed vB will involve the variables m, M, k, d, and g.
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Homework Statement


You have been asked to design a "ballistic spring system" to measure the speed of bullets. A spring whose spring constant is k is suspended from the ceiling. A block of mass M hangs from the spring. A bullet of mass m is fired vertically upward into the bottom of the block. The spring's maximum compression d is measured.

Find an expression for the bullet's speed vB.
Express your answer in terms of the variables m, M, k, d, and constant g.


Homework Equations


KE = (1/2)mv2
Ug = mgy
Us = (1/2)kx2

KEi + Ugi + Usi = KEf + Ugf + Usf

The Attempt at a Solution



This problem is going to end up getting really messy, but I am not sure how to incorporate the mass of the box (M) This is what I started with:

(1/2)mvi2 + mgyi + (1/2)kxi2 = (1/2)mvf2 + mgyf + (1/2)kxf2

now I'm assuming that mgy values are 0 because we are not given any value for the height the box is above the ground. so that would give:

(1/2)mvi2 + (1/2)kxi2 = (1/2)mvf2 + (1/2)kxf2

Incorporating the variables we are given:

(1/2)mvi2 = (1/2)kd2

however this does not include gravity (which I am sure needs to be included somewhere) or the mass of the box (M)
 
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i don't know if this help but maybe if you put the spring at rest at y=0 and then when it's compress the y=d you could incorporate then the mgy equitation therefore putting g and M in the equation
 
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