How Do You Calculate Energy Supplied in Different Time Intervals of a Circuit?

  • Thread starter Thread starter smith5753
  • Start date Start date
  • Tags Tags
    Circuit Energy
AI Thread Summary
To calculate the energy supplied in a circuit, the instantaneous power p(t) is determined by multiplying voltage v(t) = ½ t Volts and current i(t) = 12t - 4t² Amps, resulting in p(t) = 6t² - 2t³ watts. The next step involves finding the energy supplied over specified time intervals: 0 < t < 3, 3 < t < 4, and 0 < t < 4, by integrating p(t) over these ranges. There is confusion about the integration limits, with clarification needed that integration should only occur from the specified lower limit to the upper limit of each interval. The discussion emphasizes that the polynomial power function will approach infinity as t approaches infinity. Proper integration techniques are essential for accurately calculating the energy supplied in each time interval.
smith5753
Messages
2
Reaction score
0

Homework Statement



For the element shown below, v(t) = ½ t Volts and i(t) = 12t-4t2 Amps.

a)Find the instantaneous power p(t) as a function of time.

b)Find the energy supplied (this value can be negative or positive for each range) to the element for the following three time ranges:

0 < t < 3, 3 < t < 4, 0 < t < 4, those are less than or equal to.




Homework Equations



There is a picture of the circuit that show that it satisfies the Passive Sign Convention.

P(t) = V(t) i(t)

w= the integral of P(t)

The Attempt at a Solution



for part a. I multiplied the given V times the i and found p(t) to = 6t^2 - 2t^3 watts.

for part b. I attempted to take the integral of P(t) from the first point listed; 0 < t < 3

I don't understand the integration. Do i integrate from infinitie to 0, then from 0 to 3, and then from 3 to infinitie?? I am so lost at this point.
 
Physics news on Phys.org


Just integrate form 0 to 3

EDIT: also if you have infinity in the limits, the polynomial will tend to infinity as t→ inf.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top