How Do You Calculate f(x+Δx) for the Function x²+3x+2?

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it's just something thechnical



let's say i have the function x2+3x+2

when they say f(x+\Deltax)



is it (x+\Deltax)2+2(x+\Deltax)+2

or

another way?
 
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stonecoldgen said:
it's just something thechnical



let's say i have the function x2+3x+2

when they say f(x+\Deltax)



is it (x+\Deltax)2+2(x+\Deltax)+2

or

another way?

It's that. Except you have 3 in the first expression and a 2 in the second in the linear term. Typo, I guess?
 
Dick said:
It's that. Except you have 3 in the first expression and a 2 in the second in the linear term. Typo, I guess?

thanks lot and yeah, typo
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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