How Do You Calculate Final Velocities in a Spring-Mass System?

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To calculate final velocities in a spring-mass system, the minimum work needed to compress the spring is determined to be 150 joules using the work-energy principle. When both masses are released simultaneously, the conservation of momentum and energy principles must be applied to find the final velocities of each mass. The total kinetic energy is equal to the work done, leading to the equation 150 joules = 1/2(1)v^2 + 1/2(3)v^2. Since there are two unknowns (the final velocities of both masses), two equations are necessary for a solution. The discussion emphasizes the importance of applying both conservation laws to solve for the unknowns effectively.
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Homework Statement


a massless spring is between a 1-kg and 3-kg mass as shown.but it is not attached to either mass. Both masses are on a horizontal frictionless table. In an experiment, the 1 kg mass is held in place and the spring is compressed by pushing the 3 kg mass. the 3 kg mass is then released and moves off wiht a speed of 10 m/s.

a. determine the minimum work needed to compress the spring in this experiment.

b. the spring is compressed again exactly as above. but this time both masses are released simultaneously. determine the final velocity of each mass relative to teh table after the masses are released.



i've found a. by using work done=change in kinetic energy and got 150 joules.


B. i have no real idea how to start this problem, i think that the amount of work may stay the same but I am not sure. my thought is work done=totat kinetic energy so, 150 joules= 1/2(1)v^2 + 1/2(3)v^2
 
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I have not done one of these in a long time, but it appears that you will now have two unknowns. This means you NEED to have two equations. You have one. Is there another theory (equation) that you cab apply to this problem?
 
One of the equation involve the conservation of energy, the other would involve the conservation of linear momentum.
 
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