How Do You Calculate Force and Acceleration on an Inclined Plane?

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Homework Help Overview

The discussion revolves around calculating force and acceleration for a block on an inclined plane, given its mass, distance traveled, time, and coefficient of kinetic friction. The participants are exploring the relationships between various forces acting on the block, including gravitational force and frictional force.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to apply kinematic equations to find acceleration and then uses Newton's second law to relate the forces acting on the block. Questions arise regarding the calculation of the normal force and the components of gravitational force on the incline.

Discussion Status

Some participants confirm the original poster's approach to the first part of the problem, while others suggest reevaluating the calculation of the normal force by breaking gravity into components. There is ongoing exploration of how to correctly apply trigonometric functions to find the necessary forces.

Contextual Notes

Participants are discussing the implications of using the correct component of gravitational force acting perpendicular to the ramp, which is critical for accurately determining the normal force and subsequently the force of friction.

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Homework Statement


The 60 kg block starting at rest is pushed 7.8 m up a ramp at an angle θ = 26.5° to the horizontal in 15 s. If the coeficient of kinetic friction is 0.17:
What is the acceleration of block?
What is the force used to push the block up the ramp?

Homework Equations


Fnet = ma
Delta X = Vit + (1/2)at^2
Fg=ma
Fkinetic = μ * N

The Attempt at a Solution


I think I understand the first part,
7.8 = 0*15 + (1/2)(a)(15^2)
7.8 = 112.5a
.069=a

But the second part is what's giving me trouble
Do I need to make an Fnet = ma equation?
If I do I know that it would look like this
Force of Push - Force of friction = ma
Force of Push - Force of friction = (60)(.069)
Can I substitute in this equation? Fkinetic = μ * N for Fk?
Force of Push - (μ * N) = 60* .069
Fpush - (.17 * N) = 4.14

But what is my N force? I think that it would just be mass times acceleration of gravity and in that case:
Fpush - (.17 * (60 * 9.81)) = 4.14
Fpush - 100.06200 = 4.14
Fpush = 104.20200N

I'm not sure if this is right, I appreciate your help in advance.
 
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You did the first part right.

For the second part, you did everything right except your calculation of the normal force. Try drawing a force diagram of the block. On an inclined ramp, gravity doesn't act perpendicular to the plane of motion.
 
Do I just need to find the horizontal component of gravity?
 
Not the horizontal component, though you do need to break gravity into components. You need to find the component of gravity that is perpendicular to the ramp.
 
So then do I just do
Cosine (26.5) = A/H
and in this case adjacent is the force I am looking for and H is gravity
Is the gravity Fg? so I can substitute Fg=ma
60 * 9.81 = Fg

Then I have
Cosine (26.5) * (60 * 9.81) = A

Is this correct?
 
Alright well that's wrong and I'm not sure why
Cos(26.5) * H = A
Cos(26.5) * (60 x 9.81) = A
which ends up being 118.71N
When I plug that in I get
Fpush - (.17 x 118.97) = 4.14
Fpush = 24.36
And I this doesn't work, so I'm not sure what's going wrong
 

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