How Do You Calculate Heat Released When Steam Turns to Ice?

AI Thread Summary
To calculate the heat released when steam turns to ice, the process involves several phases: cooling the steam, condensing it to water, cooling the water to freezing point, freezing the water, and cooling the resulting ice. The equation Qlost + Qgained = 0 is relevant, where the heat lost by steam equals the heat gained by the ice. Each phase change and temperature change must be accounted for using the mass, heat capacity, and latent heat values. The specific heat capacity of ice (referred to as "Sice") is also necessary for the calculations. Properly setting up the problem requires careful consideration of each phase and the respective heat transfer equations.
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Homework Statement



How much heat is released freezing 75 grams of steam at 110 degrees celcius into ice at -5.1 degree celcius

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The Attempt at a Solution

I tried to do this problem but got an answer like -17101.6J. I don't need you guys to give me an answer but can you suggest how to setup a problem like this? I know Qlost+Qgained=0...so would the 2 phase changes (steam to liquid, liquid to solid) =0?
 
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Several parts:
- cooling the steam
- condensing the steam to water
- cooling the water to freezing point
- freezing
- cooling the ice
 
So would I have (Msteam*Lheatsteam)+(Mwater*Lheatwater)+(Mice*Lheatice)+(Mice*Sice+change in temp ice)=0?
 
(Mice*Sice+change in temp ice)=0?
Certainly not equal to zero - equal to the heat released that you are trying to find.

I don't know what "Sice" means. I would say
M*C*ΔT for each of the three coolings, where M is the mass, C the heat capacity per kg per degree and ΔT the change in temperature.
 

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