- #1
physiman
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1. Homework Statement
Calculate the heat energy required to convert 0.10 kg of ice at -10 degrees Celcius into steam at 100 degrees Celcius.
2. Homework Equations
E = m c dt (1)
where
E = heat energy (kJ)
m = unit mass (kg)
c = specific heat capacity (kJ/kg oC)
dt = temperature change (Kelvin or degrees Celsius)
3. The Attempt at a Solution
Given in the question:
m = 0.1 kg
dt = 100-(-10) = 110 degrees Celcius
c = 2100 J Kg^-1 K^-1 (specific heat capacity of ice)
So what I did was using the equation:
E = m c dt
E = (0.1)(2100)(110)
E = 23100 J
which would be 23.1 kJ
The problem is that the answer section of the book says 301.6 KJ which is way above my result.
What's the mistake I'm doing?
Help appreciated.
Calculate the heat energy required to convert 0.10 kg of ice at -10 degrees Celcius into steam at 100 degrees Celcius.
2. Homework Equations
E = m c dt (1)
where
E = heat energy (kJ)
m = unit mass (kg)
c = specific heat capacity (kJ/kg oC)
dt = temperature change (Kelvin or degrees Celsius)
3. The Attempt at a Solution
Given in the question:
m = 0.1 kg
dt = 100-(-10) = 110 degrees Celcius
c = 2100 J Kg^-1 K^-1 (specific heat capacity of ice)
So what I did was using the equation:
E = m c dt
E = (0.1)(2100)(110)
E = 23100 J
which would be 23.1 kJ
The problem is that the answer section of the book says 301.6 KJ which is way above my result.
What's the mistake I'm doing?
Help appreciated.