How Do You Calculate Line Current for Different Connections in a 3 Phase Line?

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To calculate line current for a 500V, 3-phase line with 3 x 15 Ohm resistors and 3 x 3.83 mH reactors, the first connection involves R and L in series, connected in wye, resulting in identical currents in each phase. For the second connection, where R and L are in parallel and connected in delta, Wye-Delta transformations or phase angle differences can be utilized to find the current. The discussion emphasizes the importance of understanding the configuration of the components and their impact on current calculations. Participants suggest methods to approach the calculations without needing phasor diagrams. Clarity on these connections is essential for accurate line current determination.
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3 x 15Ohm resistor (R) and 3 x 3.83 mH reactors (L) are connected in different ways across a 500V, 3 phase line. without drawing a phasor diagram, calculate the line current for each of the following connections:

a. R and L in series, connected in wye

b. R and L in parallel, connected in delta

i have difficulty in starting to solve...anyone could shed some light here?

thanks
 
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Well, in -a-, you just have a 15 Ohm resistor in series with a 3.83mH inductor from each phase to Neutral, right? It seems that the current in each leg would be identical and independent...

For -b-, you can look first at Wye-Delta transformations,

http://en.wikipedia.org/wiki/Y-delta_transform

or you could solve it using the phase angle differences...
 
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