How Do You Calculate Normal Force on an Inclined Plane in a Moving System?

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To calculate the normal force on an inclined plane with a moving system, the equations involve the gravitational force and the acceleration of the block on the plane. The key equations are m*g*sin(Alpha) + m*A0*cos(Alpha)=m*Ax and N + m*A0*sin(Alpha) - m*g*cos(Alpha)=m*Ay. Initially, there were three variables but only two equations, leading to confusion. It was determined that Ay equals zero since the block remains on the plane, simplifying the calculations. This realization allows for the correct calculation of the normal force N.
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Homework Statement


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Given inclined plane with mass M. The angle of inclination is Alpha (from the horizontal plane).
The plane has no friction.
On the plane block with mass m.
The whole system is moving rightwards with acceleration A0.
Find the N normal between M and m.

Homework Equations


m*g*sin(Alpha) + m*A0*cos(Alpha)=m*Ax
N + m*A0*sin(Alpha) -m*g*cos(Alpha)=m*Ay



The Attempt at a Solution


In those equations i have 3 variables and only 2 equations.
The Ax and Ay are projections of acceleration of m on the axises.
The only thought that comes to mind is to add third equation as tangent proportion between the Ax / Ay=tan(Alpha)
But i have some doubts ...
Any suggestions

Thank you in advance.
 
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Well, - i figured out the problem - the Ay is 0, since the block stays on the plane.
 
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