How Do You Calculate Norton Equivalent Circuits in Electrical Engineering?

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Discussion Overview

The discussion revolves around calculating the Norton equivalent circuit in electrical engineering, focusing on the application of mesh analysis and superposition methods to determine the Norton current and resistance. Participants are addressing a specific homework problem involving a circuit with a current source and resistors.

Discussion Character

  • Homework-related, Technical explanation, Mathematical reasoning

Main Points Raised

  • One participant states they calculated R(n) as 34 ohms after turning off independent sources and short-circuiting terminals A and B, but seeks clarification on the impact of a 2 amp current source on mesh currents I2 and I3.
  • Another participant suggests writing mesh equations to find the current in the circuit and proposes using superposition as an alternative method to solve for the total current.
  • A further reply indicates that the 2A independent source creates a relationship between the mesh currents, specifically that I3 - I2 equals 2A.
  • There is mention of using straightforward current dividers as part of the superposition method to simplify the problem.

Areas of Agreement / Disagreement

Participants appear to agree on the methods of mesh analysis and superposition as valid approaches to solving the problem, but there is no consensus on the specific values or relationships of the currents without further clarification of the circuit diagram.

Contextual Notes

Some assumptions regarding the labeling of mesh currents and the configuration of the circuit diagram are not explicitly stated, which may affect the clarity of the discussion.

Who May Find This Useful

Students and practitioners in electrical engineering, particularly those studying circuit analysis and equivalent circuits.

ihavaquestion
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Homework Statement


Find norton equivalent circuit


Homework Equations


Rn=Rth


The Attempt at a Solution


Ok i got my R(n)=34 ohms because after you turn off independent sources the resistors are in series, then I short circuited a to be and I'm trying to use mesh analysis to solve for I(n)
the problem arises with the 2 amp current source does that make I2 and I3 2 amps? help!?
 

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ihavaquestion said:

Homework Statement


Find norton equivalent circuit


Homework Equations


Rn=Rth


The Attempt at a Solution


Ok i got my R(n)=34 ohms because after you turn off independent sources the resistors are in series, then I short circuited a to be and I'm trying to use mesh analysis to solve for I(n)
the problem arises with the 2 amp current source does that make I2 and I3 2 amps? help!?

You can write the mesh equations for the circuit and calculate the current in ab.
Or you can use superposition: cancel one of the current sources and calculate the current, then activate that source and cancel the other. The total sum of the two partial currents. current is the
 
ihavaquestion said:
the problem arises with the 2 amp current source does that make I2 and I3 2 amps? help!?

You didn't label the diagram with mesh currents, so I'll guess that you have three meshes numbered from left to right in the circuit. For clockwise mesh currents i1, i2, i3, the 2A independent source will make i3 - i2 = 2A.

Note that you could also solve the problem pretty easily using superposition: you get a couple of straightforward current dividers to deal with.
 
thank you for your help
 

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