How Do You Calculate Rope Tension with Friction and Constant Velocity?

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    Rope Tension
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To calculate the tension in the rope while considering friction and constant velocity, it's essential to understand the forces acting on the block. The coefficient of kinetic friction (μk) is 0.40, and the weight of the block is 9.8 N, which provides the normal force. Since the block moves at a constant velocity of 2.3 m/s, the net force is zero, indicating that the tension in the rope must equal the frictional force. A free body diagram can help visualize the forces involved and clarify the relationship between tension, friction, and the normal force. Understanding these concepts is crucial for solving the problem accurately.
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Homework Statement


The block moves at 2.3 m/s to the left (on a flat, horizontal surface). If μk, the coefficient of friction between the block and the floor, is .40, what is the tension in the rope? Also, the weight of the block is 9.8 N

Homework Equations



No equations were given... but I used Fk=μkFn

The Attempt at a Solution


2.3=.40Fn
Fn=5.75?
I googled how to find tension.. Some told me I needed three components: Ff, Fn, and Fg and some gave an acceleration for gravity. I don't understand how to go about this problem :/
 
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PerSempre said:

Homework Statement


The block moves at 2.3 m/s to the left (on a flat, horizontal surface). If μk, the coefficient of friction between the block and the floor, is .40, what is the tension in the rope? Also, the weight of the block is 9.8 N
What rope? Is there a rope pulling this block? Is the speed constant? What does that tell you?

No equations were given... but I used Fk=μkFn
You'll need that to figure out the friction force.

The Attempt at a Solution


2.3=.40Fn
Fn=5.75?
You set a speed (2.3 m/s) equal to a force. That makes no sense! Also, Fn is given! No need to calculate it.

Start by drawing a free body diagram of the block. What forces act? What's the net force on the block?
 
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