How Do You Calculate Tension and Force Components in a Supported Beam Scenario?

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To calculate the tension and force components in a supported beam scenario, a 1320-N beam is attached to a wall and supports a 1960-N crate. The discussion emphasizes the need for understanding the moments and force components acting on the beam. Participants suggest using equations for horizontal and vertical forces, as well as torque calculations, to solve the problem. Clarification on the use of angles and the importance of defining a length for torque calculations is highlighted. A solid grasp of torque and force equilibrium is essential for finding the correct answers.
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Homework Statement



A 1320-N uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. A 1960-N crate hangs from the far end of the beam. Using the data shown in the figure, find (a) the magnitude of the tension in the wire and the magnitudes of the (b) horizontal and (c) vertical components of the force that the wall exerts on the left end of the beam.
ch09p_20.gif

Homework Equations


F=ma

The Attempt at a Solution


I'm pretty stuck on this, if someone could give me some advice that would be very helpful.
 
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hi emerica1254! :smile:

you'll need one moment and two directions :wink:
 
Can you clarify a little more?
 
hi emerica1254! :wink:

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Ive tried tension of rope =1320cos50+1960*9.8
Vertical force= 1320sin30+1960*9.8
Horizontal force= 1320cos30+1960*9.8
 
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I was using the forces from the weight of the box and bar and l also used the angle. Don't i need a length to use torque?
 
call the length L …

it'll cancel out in the end anway :smile:
 
I'm still not getting the right answer and the only equations i can think of using are the ones i already tried.
 
  • #10
show us your moments equation
 
  • #11
I'm not sure what you mean, are you talking about inertia? i know I=1/3*M*L squared for the beam
and Torque= I*angular acceleration
 
  • #12
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